x^2+x=1056

Solution for x^2+x=1056 equation:

x^2+x=1056

We move all terms to the left:

x^2+x-(1056)=0

a = 1; b = 1; c = -1056;
Δ = b2-4ac
Δ = 12-4·1·(-1056)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-65}{2*1}=\frac{-66}{2}
=-33
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+65}{2*1}=\frac{64}{2}
=32
$